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5x^2-50x=30=0
We move all terms to the left:
5x^2-50x-(30)=0
a = 5; b = -50; c = -30;
Δ = b2-4ac
Δ = -502-4·5·(-30)
Δ = 3100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3100}=\sqrt{100*31}=\sqrt{100}*\sqrt{31}=10\sqrt{31}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-10\sqrt{31}}{2*5}=\frac{50-10\sqrt{31}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+10\sqrt{31}}{2*5}=\frac{50+10\sqrt{31}}{10} $
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